Optimal. Leaf size=244 \[ \frac{4 \sqrt{\frac{x^2}{\left (\sqrt{3 x^2-1}+1\right )^2}} \left (\sqrt{3 x^2-1}+1\right ) \text{EllipticF}\left (2 \tan ^{-1}\left (\sqrt [4]{3 x^2-1}\right ),\frac{1}{2}\right )}{15 \sqrt{3} x}+\frac{2}{45} \left (3 x^2-1\right )^{3/4} x+\frac{8 \sqrt [4]{3 x^2-1} x}{15 \left (\sqrt{3 x^2-1}+1\right )}-\frac{1}{9} \sqrt{\frac{2}{3}} \tan ^{-1}\left (\frac{\sqrt{\frac{3}{2}} x}{\sqrt [4]{3 x^2-1}}\right )-\frac{1}{9} \sqrt{\frac{2}{3}} \tanh ^{-1}\left (\frac{\sqrt{\frac{3}{2}} x}{\sqrt [4]{3 x^2-1}}\right )-\frac{8 \sqrt{\frac{x^2}{\left (\sqrt{3 x^2-1}+1\right )^2}} \left (\sqrt{3 x^2-1}+1\right ) E\left (2 \tan ^{-1}\left (\sqrt [4]{3 x^2-1}\right )|\frac{1}{2}\right )}{15 \sqrt{3} x} \]
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Rubi [A] time = 0.185831, antiderivative size = 244, normalized size of antiderivative = 1., number of steps used = 12, number of rules used = 7, integrand size = 24, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.292, Rules used = {440, 230, 305, 220, 1196, 321, 398} \[ \frac{2}{45} \left (3 x^2-1\right )^{3/4} x+\frac{8 \sqrt [4]{3 x^2-1} x}{15 \left (\sqrt{3 x^2-1}+1\right )}-\frac{1}{9} \sqrt{\frac{2}{3}} \tan ^{-1}\left (\frac{\sqrt{\frac{3}{2}} x}{\sqrt [4]{3 x^2-1}}\right )-\frac{1}{9} \sqrt{\frac{2}{3}} \tanh ^{-1}\left (\frac{\sqrt{\frac{3}{2}} x}{\sqrt [4]{3 x^2-1}}\right )+\frac{4 \sqrt{\frac{x^2}{\left (\sqrt{3 x^2-1}+1\right )^2}} \left (\sqrt{3 x^2-1}+1\right ) F\left (2 \tan ^{-1}\left (\sqrt [4]{3 x^2-1}\right )|\frac{1}{2}\right )}{15 \sqrt{3} x}-\frac{8 \sqrt{\frac{x^2}{\left (\sqrt{3 x^2-1}+1\right )^2}} \left (\sqrt{3 x^2-1}+1\right ) E\left (2 \tan ^{-1}\left (\sqrt [4]{3 x^2-1}\right )|\frac{1}{2}\right )}{15 \sqrt{3} x} \]
Antiderivative was successfully verified.
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Rule 440
Rule 230
Rule 305
Rule 220
Rule 1196
Rule 321
Rule 398
Rubi steps
\begin{align*} \int \frac{x^4}{\left (-2+3 x^2\right ) \sqrt [4]{-1+3 x^2}} \, dx &=\int \left (\frac{2}{9 \sqrt [4]{-1+3 x^2}}+\frac{x^2}{3 \sqrt [4]{-1+3 x^2}}+\frac{4}{9 \left (-2+3 x^2\right ) \sqrt [4]{-1+3 x^2}}\right ) \, dx\\ &=\frac{2}{9} \int \frac{1}{\sqrt [4]{-1+3 x^2}} \, dx+\frac{1}{3} \int \frac{x^2}{\sqrt [4]{-1+3 x^2}} \, dx+\frac{4}{9} \int \frac{1}{\left (-2+3 x^2\right ) \sqrt [4]{-1+3 x^2}} \, dx\\ &=\frac{2}{45} x \left (-1+3 x^2\right )^{3/4}-\frac{1}{9} \sqrt{\frac{2}{3}} \tan ^{-1}\left (\frac{\sqrt{\frac{3}{2}} x}{\sqrt [4]{-1+3 x^2}}\right )-\frac{1}{9} \sqrt{\frac{2}{3}} \tanh ^{-1}\left (\frac{\sqrt{\frac{3}{2}} x}{\sqrt [4]{-1+3 x^2}}\right )+\frac{2}{45} \int \frac{1}{\sqrt [4]{-1+3 x^2}} \, dx+\frac{\left (4 \sqrt{x^2}\right ) \operatorname{Subst}\left (\int \frac{x^2}{\sqrt{1+x^4}} \, dx,x,\sqrt [4]{-1+3 x^2}\right )}{9 \sqrt{3} x}\\ &=\frac{2}{45} x \left (-1+3 x^2\right )^{3/4}-\frac{1}{9} \sqrt{\frac{2}{3}} \tan ^{-1}\left (\frac{\sqrt{\frac{3}{2}} x}{\sqrt [4]{-1+3 x^2}}\right )-\frac{1}{9} \sqrt{\frac{2}{3}} \tanh ^{-1}\left (\frac{\sqrt{\frac{3}{2}} x}{\sqrt [4]{-1+3 x^2}}\right )+\frac{\left (4 \sqrt{x^2}\right ) \operatorname{Subst}\left (\int \frac{x^2}{\sqrt{1+x^4}} \, dx,x,\sqrt [4]{-1+3 x^2}\right )}{45 \sqrt{3} x}+\frac{\left (4 \sqrt{x^2}\right ) \operatorname{Subst}\left (\int \frac{1}{\sqrt{1+x^4}} \, dx,x,\sqrt [4]{-1+3 x^2}\right )}{9 \sqrt{3} x}-\frac{\left (4 \sqrt{x^2}\right ) \operatorname{Subst}\left (\int \frac{1-x^2}{\sqrt{1+x^4}} \, dx,x,\sqrt [4]{-1+3 x^2}\right )}{9 \sqrt{3} x}\\ &=\frac{2}{45} x \left (-1+3 x^2\right )^{3/4}+\frac{4 x \sqrt [4]{-1+3 x^2}}{9 \left (1+\sqrt{-1+3 x^2}\right )}-\frac{1}{9} \sqrt{\frac{2}{3}} \tan ^{-1}\left (\frac{\sqrt{\frac{3}{2}} x}{\sqrt [4]{-1+3 x^2}}\right )-\frac{1}{9} \sqrt{\frac{2}{3}} \tanh ^{-1}\left (\frac{\sqrt{\frac{3}{2}} x}{\sqrt [4]{-1+3 x^2}}\right )-\frac{4 \sqrt{\frac{x^2}{\left (1+\sqrt{-1+3 x^2}\right )^2}} \left (1+\sqrt{-1+3 x^2}\right ) E\left (2 \tan ^{-1}\left (\sqrt [4]{-1+3 x^2}\right )|\frac{1}{2}\right )}{9 \sqrt{3} x}+\frac{2 \sqrt{\frac{x^2}{\left (1+\sqrt{-1+3 x^2}\right )^2}} \left (1+\sqrt{-1+3 x^2}\right ) F\left (2 \tan ^{-1}\left (\sqrt [4]{-1+3 x^2}\right )|\frac{1}{2}\right )}{9 \sqrt{3} x}+\frac{\left (4 \sqrt{x^2}\right ) \operatorname{Subst}\left (\int \frac{1}{\sqrt{1+x^4}} \, dx,x,\sqrt [4]{-1+3 x^2}\right )}{45 \sqrt{3} x}-\frac{\left (4 \sqrt{x^2}\right ) \operatorname{Subst}\left (\int \frac{1-x^2}{\sqrt{1+x^4}} \, dx,x,\sqrt [4]{-1+3 x^2}\right )}{45 \sqrt{3} x}\\ &=\frac{2}{45} x \left (-1+3 x^2\right )^{3/4}+\frac{8 x \sqrt [4]{-1+3 x^2}}{15 \left (1+\sqrt{-1+3 x^2}\right )}-\frac{1}{9} \sqrt{\frac{2}{3}} \tan ^{-1}\left (\frac{\sqrt{\frac{3}{2}} x}{\sqrt [4]{-1+3 x^2}}\right )-\frac{1}{9} \sqrt{\frac{2}{3}} \tanh ^{-1}\left (\frac{\sqrt{\frac{3}{2}} x}{\sqrt [4]{-1+3 x^2}}\right )-\frac{8 \sqrt{\frac{x^2}{\left (1+\sqrt{-1+3 x^2}\right )^2}} \left (1+\sqrt{-1+3 x^2}\right ) E\left (2 \tan ^{-1}\left (\sqrt [4]{-1+3 x^2}\right )|\frac{1}{2}\right )}{15 \sqrt{3} x}+\frac{4 \sqrt{\frac{x^2}{\left (1+\sqrt{-1+3 x^2}\right )^2}} \left (1+\sqrt{-1+3 x^2}\right ) F\left (2 \tan ^{-1}\left (\sqrt [4]{-1+3 x^2}\right )|\frac{1}{2}\right )}{15 \sqrt{3} x}\\ \end{align*}
Mathematica [C] time = 0.0929506, size = 177, normalized size = 0.73 \[ \frac{2 x \left (-3 \sqrt [4]{1-3 x^2} x^2 F_1\left (\frac{3}{2};\frac{1}{4},1;\frac{5}{2};3 x^2,\frac{3 x^2}{2}\right )-\frac{4 F_1\left (\frac{1}{2};\frac{1}{4},1;\frac{3}{2};3 x^2,\frac{3 x^2}{2}\right )}{\left (3 x^2-2\right ) \left (x^2 \left (2 F_1\left (\frac{3}{2};\frac{1}{4},2;\frac{5}{2};3 x^2,\frac{3 x^2}{2}\right )+F_1\left (\frac{3}{2};\frac{5}{4},1;\frac{5}{2};3 x^2,\frac{3 x^2}{2}\right )\right )+2 F_1\left (\frac{1}{2};\frac{1}{4},1;\frac{3}{2};3 x^2,\frac{3 x^2}{2}\right )\right )}+3 x^2-1\right )}{45 \sqrt [4]{3 x^2-1}} \]
Warning: Unable to verify antiderivative.
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Maple [F] time = 0.076, size = 0, normalized size = 0. \begin{align*} \int{\frac{{x}^{4}}{3\,{x}^{2}-2}{\frac{1}{\sqrt [4]{3\,{x}^{2}-1}}}}\, dx \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{x^{4}}{{\left (3 \, x^{2} - 1\right )}^{\frac{1}{4}}{\left (3 \, x^{2} - 2\right )}}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [F] time = 0., size = 0, normalized size = 0. \begin{align*}{\rm integral}\left (\frac{{\left (3 \, x^{2} - 1\right )}^{\frac{3}{4}} x^{4}}{9 \, x^{4} - 9 \, x^{2} + 2}, x\right ) \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{x^{4}}{\left (3 x^{2} - 2\right ) \sqrt [4]{3 x^{2} - 1}}\, dx \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{x^{4}}{{\left (3 \, x^{2} - 1\right )}^{\frac{1}{4}}{\left (3 \, x^{2} - 2\right )}}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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